(2x-3)^2/7=4

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Solution for (2x-3)^2/7=4 equation:


x in (-oo:+oo)

((2*x-3)^2)/7 = 4 // - 4

((2*x-3)^2)/7-4 = 0

((2*x-3)^2)/7+(-4*7)/7 = 0

(2*x-3)^2-4*7 = 0

4*x^2-12*x-19 = 0

4*x^2-12*x-19 = 0

4*x^2-12*x-19 = 0

DELTA = (-12)^2-(-19*4*4)

DELTA = 448

DELTA > 0

x = (448^(1/2)+12)/(2*4) or x = (12-448^(1/2))/(2*4)

x = (8*7^(1/2)+12)/8 or x = (12-8*7^(1/2))/8

(x-((12-8*7^(1/2))/8))*(x-((8*7^(1/2)+12)/8)) = 0

((x-((12-8*7^(1/2))/8))*(x-((8*7^(1/2)+12)/8)))/7 = 0

((x-((12-8*7^(1/2))/8))*(x-((8*7^(1/2)+12)/8)))/7 = 0 // * 7

(x-((12-8*7^(1/2))/8))*(x-((8*7^(1/2)+12)/8)) = 0

( x-((12-8*7^(1/2))/8) )

x-((12-8*7^(1/2))/8) = 0 // + (12-8*7^(1/2))/8

x = (12-8*7^(1/2))/8

( x-((8*7^(1/2)+12)/8) )

x-((8*7^(1/2)+12)/8) = 0 // + (8*7^(1/2)+12)/8

x = (8*7^(1/2)+12)/8

x in { (12-8*7^(1/2))/8, (8*7^(1/2)+12)/8 }

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